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Which one of the following has the regular tetrahedral structure ?

\left ( Atomic\: nos:\: B=5,S=16,Ni=28,Xe=54 \right )

  • Option 1)

    XeF_{4}

  • Option 2)

    SF_{4}

  • Option 3)

    BF{_{4}}^{-}

  • Option 4)

    \left [ Ni\left ( CN \right )_{4} \right ]^{2-}

 

Answers (2)

best_answer

As we learnt in

sp3 hybridisation -

when one s - and three p - orbital belonging to the same shell of an atom mix together to form four new equivalent orbitals is called sporbital.

- wherein

Shape Tetrahedral 

 

 

   

 

 

Molecule                   Shape

XeF4                        Square Planar

SF4                          See Saw Shaped

BF_{4}^{-}                     Tetrahedral

\left [ Ni\left ( CN \right )_{4} \right ]^{2-}     Square Planar

 

 

 

 

 


Option 1)

XeF_{4}

This option is incorrect. 

Option 2)

SF_{4}

This option is incorrect. 

Option 3)

BF{_{4}}^{-}

This option is correct. 

Option 4)

\left [ Ni\left ( CN \right )_{4} \right ]^{2-}

This option is incorrect. 

Posted by

Aadil

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