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A block of mass 10 kg is kept on a rough inclined as shown in figure. The coefficient of friction between the block and the surface is 0.6. Two forces of magnitude 3N & P Newton are acting of the block as shown figure. If friction on the block is acting upwards then minimum value of P for which the block remains at rest is

Answers (1)

Use $F=\mu R$

3 + mg sin $\theta$ = P + $\mu$ mg cos $\theta$

$3 + \frac{100}{\sqrt{2}} = P + 0.6 \times \frac{100}{\sqrt{2}}$

P = 32 N

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