Get Answers to all your Questions

header-bg qa

  1. A block of mass 10 kg is kept on a rough inclined as shown in figure. The coefficient of friction between the block and the surface is 0.6. Two forces of magnitude 3N & P Newton are acting of the block as shown figure. If friction on the block is acting upwards then minimum value of P for which the block remains at rest is 

Answers (1)

Use F=\mu R


3 + mg sin \theta = P + \mu mg cos \theta

3 + \frac{100}{\sqrt{2}} = P + 0.6 \times \frac{100}{\sqrt{2}}

P = 32 N

Posted by

Safeer PP

View full answer

Crack JEE Main with "AI Coach"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support