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Three reactions involving H^{2}PO_{4}^{-} are given below:

(i)\: \: H_{3}PO_{4}+H_{2}O\rightarrow H_{3}O^{+}+H_{2}PO_{4}^{-}

(ii)\: \: H_{2}PO_{4}^{-}+H_{2}O\rightarrow HPO_{4}^{2-}+H_{3}O^{+}

(iii)\: \: H_{2}PO_{4}^{-}+OH^{-}\rightarrow H_{3}PO_{4}+O^{2-}

In which of the above does H^{2}PO_{4}^{-} act as an acid?

  • Option 1)

    (i) only

  • Option 2)

    (ii) only

  • Option 3)

    (i) and (ii) both

  • Option 4)

    (iii) only

 

Answers (1)

best_answer

As we have learned

Ionization reaction of dibasic acid -

H_{2}X(aq)\rightleftharpoons H^{+}(aq)+H\bar{X}(aq)


\bar{H}X(aq)\rightleftharpoons H^{+}(aq)+X^{2-}(aq)

- wherein

K_{a1}=\frac{[H^{+}]\:[\bar{H}X]}{[H_{2}X]}


K_{a2}=\frac{[H^{+}]\:[X^{2-}]}{[{H}X^{-}]}


K_{a1}\:and\:K_{a2}   are called first and second ionization constant.

 

 In H_2PO_{4}^{-} + H_2O\rightarrow HPO_{4}^{2-} + H_3O^+

H^+  is liberated in product side , so 

H_2PO_{4}^{-}   is acting as an acid 

 

 

 

 

 


Option 1)

(i) only

Option 2)

(ii) only

Option 3)

(i) and (ii) both

Option 4)

(iii) only

Posted by

SudhirSol

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