Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me understand! Number of atoms in the unit cell of Na (BCC) and Mg (FCC) are respectively

Number of atoms in the unit cell of Na (BCC) and Mg (FCC) are respectively

  • Option 1)

    4 and 4

  • Option 2)

    2 and 4

  • Option 3)

    4 and 2

  • Option 4)

    1 and 1

 

Answers (1)

best_answer

Number of atom in BCC unit cell = 8\times \frac{1}{8}+1=2

Number of atom in FCC unit cell = 6\times \frac{1}{2}+8\times \frac{1}{8}=4

 

No. of atoms(z) for face centered unit cell -

Lattice points: at corners and face centers of unit cell.

For face centered cubic (FCC), z=4.

- wherein

 

 


Option 1)

4 and 4

This is incorrect

Option 2)

2 and 4

This is correct

Option 3)

4 and 2

This is incorrect

Option 4)

1 and 1

This is incorrect

Posted by

divya.saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 Registration Live: NTA session 1 application last date today; official website, syllabus
anam-khan

JEE Main 2025 session 1 registration ends today at jeemain.nta.nic.in; application correction from November 26
anam-khan

JEE Main 2025 registration ends tomorrow; changes introduced in exam this year

Latest Question