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  • I have a doubt, kindly clarify. - Consider a tank made of glass (refractive index 1.5) with a thick bottom. It is filled with a liquid - Optics - JEE Main

Consider a tank made of glass (refractive index 1.5) with a thick bottom. It is filled with a liquid of refractive index \mu . A student finds that, irrespective of what the incident angle i (see figure) is for a beam of light entering the liquid,the light reflected from the liquidglass interface is never completely polarized. For this to happen,the minimum value of \mu is :

  • Option 1)

    \sqrt{\frac{5}{3}}\:

  • Option 2)

    \: \frac{3}{\sqrt{5}}\:

  • Option 3)

    \: \frac{5}{\sqrt{3}}\:

  • Option 4)

    \: \frac{4}{3}

Answers (2)

best_answer

 

Critical angle -

\sin i_{c} = Refractive index of rarer medium / Refractive index of denser medium = n_{21}

- wherein

When angle of incidence of a travelling from a dence medium to rarer medium is greater than critical angle, no refraction occurs.

 

C < ib

ib \rightarrow brewster angle

C \rightarrow critical angle

sin C < sin ib 

For air \rightarrow liquid

sin 90 = \musin C

sin c = \frac{1}{\mu}

since tan ib = \frac{1.5}{\mu}

sin C < sin ib

\Rightarrow \frac{1}{\mu} < \frac{1.5}{\sqrt{\mu^{2} + (1.5) ^{2}}}

\Rightarrow \mu < \frac{3}{\sqrt{5}}


Option 1)

\sqrt{\frac{5}{3}}\:

Option 2)

\: \frac{3}{\sqrt{5}}\:

Option 3)

\: \frac{5}{\sqrt{3}}\:

Option 4)

\: \frac{4}{3}

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Why are we applying sin90= u rel c for air liquid interference

Shouldn't we apply critical angle theory for liquid glass interference

And another thing a ray suffers tir only when it travels from denser to rarer medium 

That clearly means density of liquid must be greater than 1.5

Plz help

Posted by

Sampu

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