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  • If first excitation potential of a hydrogen like atom is V electron volt, then the ionization energy of this atom will be:  Option: 1

If first excitation potential of a hydrogen like atom is V electron volt, then the ionization energy of this atom will be:

 

Option: 1

V electron volt


Option: 2

\frac{3V}{4} electron volt


Option: 3

\frac{4V}{3} electron volt


Option: 4

cannot be calculated


Answers (1)

best_answer

 

Energy emitted due to transition of electron -

\Delta E= Rhcz^{2}\left ( \frac{1}{n_{f}\, ^{2}}-\frac{1}{n_{i}\, ^{2}} \right )

\frac{1}{\lambda }= Rz^{2}\left ( \frac{-1}{n_{i}\, ^{2}}+\frac{1}{n_{f}\, ^{2}} \right )

- wherein

R= R hydberg\: constant

n_{i}= initial state \\n_{f}= final \: state

 

 

First excitation energy = RhC \left ( \frac{1}{1^{2}} - \frac{1}{2^{2}} \right )

= RhC\frac{3}{4}

\therefore \frac{3}{4}RhC = V e.v

\therefore RhC = \frac{4V}{3}e.v

Posted by

rishi.raj

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