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  •  If    <img alt="\mathrm{f\left(x^2\right)=|\log | x||}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7Bf%5Cleft%28x%5E2%5Cright%29%3D%7C%5Clog%20%7C%20x%7C%7C

 If    \mathrm{f\left(x^2\right)=|\log | x||}  then

Option: 1

f(x) is continuous and differentiable for all x in its domain


Option: 2

f(x) is continuous for all for all x in its domain but not differentiable at \mathrm{x= \pm 1} 


Option: 3

f(x) is neither continuous nor differentiable at \mathrm{x= \pm 1}


Option: 4

none of these.


Answers (1)

best_answer

It is evident from the graph of  \mathrm{f(x)=|\log | x||}  that f(x) is everywhere continuous but not differentiable at \mathrm{x= \pm 1} 

Posted by

Ritika Jonwal

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