Get Answers to all your Questions

header-bg qa

If the charge on a capacitor is increased by 2 C, the energy stored in it increases by 44%. The original charge on the capacitor is (in C)

Option: 1

10


Option: 2

20


Option: 3

30


Option: 4

40


Answers (1)

best_answer

\text{Let the initial and final charge of capacitor be} \ \mathrm{Q}_{\mathrm{i}} \ \text{and} \ \mathrm{Q}_{\mathrm{f}} \ \text{respectively} \\ \begin{array}{l} Q_{f}=Q_{i}+2 \rightarrow \text { (Given) } \\ \\ E_{f}=E_{i}+\frac{44}{100} \times E_{i} \text { (Given) } \\ \\ E_{f}=1.44 E_{i} \end{array} \\ \text{Where},\\ \mathrm{E}_{\mathrm{f}}\ \text{and} \mathrm{E}_{\mathrm{i}} \ \text{are the final and initial energy stored in the capacitor} \\ \begin{array}{c} \\ \frac{1}{2} \frac{Q_{f}^{2}}{C}=(1.44) \times \frac{1}{2} \frac{Q_{i}^{2}}{C} \\ Q_{f}=1.2 Q_{i} \\ \text { But } Q_{f}=Q_{i}+2 \\ \therefore Q_{i} 2 Q_{i}=2 \\ \therefore Q_{i}=10 \mathrm{C} \\ \therefore Q_{f}=12 \mathrm{C} \end{array} \\ \text{The original change on the Capacitor is} 10\ \mathrm{C} \\ \text{The correct option is} \ (1)

Posted by

Irshad Anwar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE