Get Answers to all your Questions

header-bg qa

If the electronegativity difference is 1.7 the bond is:

Option: 1

60% ionic


Option: 2

40% covalent


Option: 3

50% covalent and 50% ionic


Option: 4

None


Answers (1)

best_answer

As we have learnt,

 

Scale for measuring electronegativity and application of EN -

Nature of Bond: From the electronegativity values of respective atoms, the nature of bond can be estimated.

(i) When the electronegativity difference between two atoms i.e, MA- MB = 0, then the bond is purely covalent.

(ii) When MA- MB  is small, then the bond is polar but covalent.

(iii) When MA- MB is 1.9, then the bond is 50% ionic and 50% covalent.

(iv) When MA- MB  is more than 1.9, the bond is very much ionic and less covalent.

      The percentage of ionic character is given by the following formula:

      Percentage of ionic character = 16(MA - MB) + 3.5(MA - MB)2

      Where MA and MB are the electronegativities of two bonded atoms i.e, A and B.

 

The electronegativity difference between two atoms gives an idea about the nature of the bond between them.

If the electronegativity difference is 1.7, the bond is 50% ionic and 50% covalent. With the increased difference, the ionic character increases.

Hence, option number (3) is correct

Posted by

Rishi

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE