Get Answers to all your Questions

header-bg qa

If the two glass plates have water between them and are separated by very small distance (see figure), it is very difficult to pull them apart. It is because the water in between  forms cylindrical surface on the side that gives rise to lower pressure in the water in comparison to atmosphere. If the radius of the cylindrical surface is R and surface tension of water is T then the pressure in water between the plates is lower by :

Option: 1

\frac{T}{4R}


Option: 2

\frac{T}{2R}


Option: 3

\frac{4T}{R}


Option: 4

\frac{2T}{R}


Answers (1)

best_answer

Excess pressure inside a drop or an air bubble is given by \Delta P = \frac{2T}{R}
where T and Rare the surface tension and radius of drop.


Here, the figure show that the water between the plates forms a curved surface, similar to that formed by air bubble inside the water.


So, pressure in water between the plates is lowered by \frac{2T}{R}

Posted by

Pankaj Sanodiya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE