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  • <img alt="\underset{[1 \text { mole] }}{\text { Amino acid }} \frac{\mathrm{NaOH}+\mathrm{CaO}}{\Delta} \text { gas evolved } \xrightarrow[\text { Lime water }]{\text { Pass in }} \underset{0.1999

\underset{[1 \text { mole] }}{\text { Amino acid }} \frac{\mathrm{NaOH}+\mathrm{CaO}}{\Delta} \text { gas evolved } \xrightarrow[\text { Lime water }]{\text { Pass in }} \underset{0.1999 \mathrm{~kg}}{\text { Salt }}

Amino acid has:

Option: 1

Two NH2 groups


Option: 2

Two –COOH groups
 


Option: 3

One –COOH group 


Option: 4

Three – COOH groups


Answers (1)

\Rightarrow No. of moles of \mathrm{CaCO}_3=\frac{200}{100}=\text {2 moles }

Hence, No of moles of \mathrm{CO}_2\; \; \text{formed} - \text{2\; moles}
\therefore  The no. of  -\mathrm{COOH} groups present = 2

Posted by

Kshitij

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