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In a reaction, \mathrm{X_2 + 2Y_2 \rightarrow 2XY2}, the X disappears at

Option: 1

Half the rate as that of disappearance of Y 


Option: 2

The same rate as that of disappearance of Y


Option: 3

The same rate as that of appearance of  \mathrm{XY_2 }


Option: 4

Twice the rate as that of appearance of  \mathrm{XY_2}


Answers (1)

best_answer

For a reaction,  \mathrm{\mathrm{aA}+\mathrm{bB} \rightarrow products.}
We know, rate of reaction   \mathrm{=-\frac{1}{a} x \frac{d[A]}{d t}=-\frac{1}{b} x \frac{d[B]}{d t}.}
Hence, rate of disappearance of   \mathrm{X=-\frac{d[X]}{d t}=-\frac{1}{2} \frac{d[Y]}{d t}=\frac{1}{2} x}

rate of disappearance of Y.

Posted by

Suraj Bhandari

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