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In a Screw Gauge, fifth division of the circular scale coincides with the reference line when the ratchet is closed.There are 50 divisions on the circular scale,and the main scale moves by 0.5 mm on a complete rotation. For a particular observation the reading on the main scale is 5 mm and the 20th division of the circular scale coincides with reference line. Calculate the true reading.
Option: 1 5\cdot 20\, mm
Option: 2 5\cdot 00\, mm
Option: 3 5\cdot 15\, mm
Option: 4 5\cdot 25\, mm

Answers (1)

best_answer

\text{No of CSD} = 50
pitch= 0\cdot 5\, mm
MSR= 5\, mm
CSD= 20\, division
CSR= LC\times CSD
            = \left ( \frac{pitch}{\text{No of CSD}} \right )\times CSD
           = \frac{0\cdot 5\times 10^{-3}}{50}\times\, 20
           = 2\times 10^{-4}\, m
CSR=0\cdot 2\, mm
Zero\,\: error= \left ( LC \right )\times 5
                         = 10^{-5}\times5= 0\cdot 05\, mm
True\, reading= MSR+CSR+\left ( Zero\: conection \right )
                             = 5+0\cdot 2+\left ( -0\cdot 05 \right )
\rightarrow True\: reading= 5\cdot 15\, mm
The correct option is (3)

                      

 

Posted by

vishal kumar

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