In an estimation of bromine by Carius method, 1.6 g of an organic compound gave 1.88 g of AgBr. The mass % of Bromine in the compound is:
Moles of
Thus, the mole of AgBr = 0.01
Thus, moles of bromine in organic compound = 0.8 g
Now, % of bromine is given as:
Thus, the correct answer is 50.
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