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  • In how many ways 18 different girls can be divided into three teams in such a way that they get two, six and ten girls?Option: 1 <img alt="

In how many ways 18 different girls can be divided into three teams in such a way that they get two, six and ten girls?

Option: 1

5250960


Option: 2

6126122


Option: 3

14702688


Option: 4

147026880


Answers (1)

best_answer

Number of ways of dividing (m+n+p)(where m \neq n \neq p ) things into three unequal

groups of size m,n,p is =\frac{(m+n+p) !}{m ! n ! p !}

Here  m=2, n=6, p=10

Then, the total number of ways: 

\frac{18 !}{2 ! 6 ! 10 !}=1225224

 

Posted by

Divya Prakash Singh

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