Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • In terms of resistance R and time T, the dimensions of ratio \frac{\mu }{\epsilon } of the permeability \mu and permittivity \epsilon is :

In terms of resistance R and time T, the dimensions of ratio  \frac{\mu }{\epsilon }  of the permeability \mu  and permittivity \epsilon is :

Answers (1)

DIMENSION OF PERMEABILITY \mu = [MLT^{-2}I^{-2}]

DIMENSION OF PERMITTIVITY \epsilon = [M^{-1}L^{-3}T^{4}I^{2}]

DIMENSION OF  \mu/\epsilon = [M^{2}L^{4}T^{-6}I^{-4}]

DIMENSION OF RESISTANCE = [ML^{2}T^{-3}I^{-2}] = [R]

As we can see

DIMENSION OF \mu/\epsilon in terms of R and T= [R^{2}]

Posted by

Satyajeet Kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 response sheet errors: Delhi HC allows student to apply for JEE Adv, seeks NTA explanation
anam-khan

Four Kashmiri girls defy the odds, score 99+ percentile in JEE Main 2025
anam-khan

JEE, NEET, CUET coaching centres: Assam, Rajasthan have framed laws, but will they work?

Latest Question