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  • In the circuit shown in figure, the current in  resistance is: <img alt="" src="https://cdn.e

In the circuit shown in figure, the current in 3 \Omega resistance is:

 

 

Option: 1

1A


Option: 2

\frac{1}{7}A


Option: 3

\frac{5}{7}A


Option: 4

\frac{15}{7}A


Answers (1)

best_answer

From mesh (2) 2 \mathrm{l}_1=6 \mathrm{I}_2


From mesh (1) (Whole loop)
\begin{aligned} & 10-2\left(\mathrm{I}_1+\mathrm{I}_2\right)-6 \mathrm{I}_2=0 \\ & \text { or } \quad 14 \mathrm{I}_2=10 \text { or } \mathrm{I}_2=\frac{5}{7} \mathrm{~A} \end{aligned}

Posted by

manish painkra

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