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  • In the given AC circuit, when switch S is at position 1, the source emf leads current by  . Now, if the

In the given AC circuit, when switch S is at position 1, the source emf leads current by \pi / 6 . Now, if the switch is at potion 2, then

                                                 

Option: 1

current leads source emf by \frac{\pi}{4}


Option: 2

current leads source emf by \frac{\pi}{3}


Option: 3

source emf leads current by \frac{\pi}{4}


Option: 4

source emf leads current by \frac{\pi}{3}


Answers (1)

best_answer

\mathrm{\begin{aligned} & \text { In position }-1 \\ & \tan \frac{\pi}{6}=\frac{\omega \mathrm{L}}{\mathrm{R}}=\frac{(1000)\left(\sqrt{3} \times 10^{-3}\right)}{\mathrm{R}} \quad \text { or } \quad \frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{\mathrm{R}} \\ & \therefore \mathrm{R}=3 \Omega \\ & \text { In position }-2 \\ & \tan \phi=\frac{\mathrm{X}_{\mathrm{C}}}{\mathrm{R}}=\frac{(1 / \omega \mathrm{C})}{\mathrm{r}} \\ & =\frac{1}{\left(1000 \times \frac{1000}{3} \times 10^{-6}\right)} \\ & \therefore \phi=\frac{\pi}{4} \end{aligned} }

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