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in Triangle PQR, if (p+q+r)(p+q-r)=2pq then what is value of angle R?

Option: 1

\frac{\pi}{3}


Option: 2

\frac{\pi}{2}


Option: 3

\frac{\pi}{6}


Option: 4

\frac{\pi}{4}


Answers (1)

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Basic relation b/w sides and angle of triangle and Sine Rule -

Basic relation b/w sides and angle of triangle and Sine Rule

 

In this section, Properties and solution of Triangle. We will be using some standard symbols.

 In ΔABC, the angles are denoted by capital letters A, B and C and the length of the sides opposite to these angles are denoted by small letters a, b and c respectively.

 

\mathrm{\begin{array}{l}{ \angle B A C=A} \\ { \angle A B C=B} \\ { \angle B C A=C}\end{array}}

 

Sides of the ΔABC

AB = c, AC = b, and  BC = a

 

\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}

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\\(p+q+r)(p+q-r)=2pq\\ (p+q)^2-(r)^2=2pq\\ p^2+q^2-(r)^2=0\\ \angle R=\frac{\pi}{2}

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Ritika Harsh

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