The amount of anhydrous present in 250 ml of 0.25 M solution is
6.225 g
66.25 g
6.0 g
6.625 g
As we learned
Concentration term -
To represent the amount of solute present in the solution.
-
Option 1)
6.225 g
Option 2)
66.25 g
Option 3)
6.0 g
Option 4)
6.625 g
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