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  • of an octahedral metal complex with formula <img alt="\mathrm{MCl}_{3} \cdot 2 \mathrm{~L}" src="https://entrancecorner.codecogs.com/gif.latex?%5Cm

1 \mathrm{~mol} of an octahedral metal complex with formula \mathrm{MCl}_{3} \cdot 2 \mathrm{~L} on reaction with excess of \mathrm{AgNO}_{3} gives 1 \mathrm{~mol}$ of $\mathrm{AgCl}. The denticity of Ligand \mathrm{L} is ____________.(Integer answer)
 

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Since,1 mole of \mathrm{AgCl} is obtained, the complex  contains only one \mathrm{Cl^{\ominus }} ion outside the co-ordination sphere.

The complex can be represented as \mathrm{\left [ MCl_{2}L_{2} \right ]Cl}

Now, since the co-ordination number is 6, the ligand L has to be a bidentate ligand.

Hence, the answer is 2

Posted by

sudhir.kumar

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