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  • One combination of Li, Na and K in excess of air, the major oxides formed, respectively are:Option: 1

One combination of Li, Na and K in excess of air, the major oxides formed, respectively are:
Option: 1 \mathrm{Li}_{2} \mathrm{O}_{2}, \mathrm{Na}_{2} \mathrm{O}_{2} \text { and } \mathrm{K}_{2} \mathrm{O}_{2}
Option: 2 \mathrm{Li}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{O}_{2} \text { and } \mathrm{KO}_{2}
Option: 3 \mathrm{Li}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{O} \text { and } \mathrm{K}_{2} \mathrm{O}_{2}
Option: 4 \mathrm{Li}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{O}_{2} \text { and } \mathrm{K}_{2} \mathrm{O}

Answers (1)

best_answer

The formed oxides will be - 

\mathrm{Li}+\mathrm{O}_{2}\textup{ (excess)} \rightarrow \mathrm{Li}_{2} \mathrm{O} \text { (Major oxides) }\mathrm{Na}+\mathrm{O}_{2}\textup{ (excess)} \rightarrow \mathrm{Na}_{2} \mathrm{O}_2 \text { (Major oxides) }\mathrm{K}+\mathrm{O}_{2}\textup{ (excess)} \rightarrow \mathrm{K} \mathrm{O}_2 \text { (Major oxides) }

Therefore, the correct option is (2).

Posted by

Kuldeep Maurya

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