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One main scale division of a vernier calliper is (b + 1) cm and nth division of vernier scale coincide with (n - 2)th division of main scale. Find the least count of callipers

Option: 1

\frac{2(b+1)}{n} \, cm


Option: 2

2 (b+1) cm


Option: 3

(n+1) cm


Option: 4

(b+2) cm


Answers (1)

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\begin{aligned} & \text { 1M.S.D }=(b+1) \mathrm{cm} \text {. } \\ & 1 \text { V.S.D }=\frac{(n-2) \times(b+1)}{n} \\ & \text { Least count }(L \cdot C)=\text { 1M.S.D- 1 V.S.D } \\ & =(b+1)-\frac{(n-2)(b+1)}{n} \\ & =\frac{n(b+1)-(n(b+1)-2(b+1))}{n} \\ & =\frac{2(b+1)}{n} \mathrm{~cm} \\ & \end{aligned}

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sudhir.kumar

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