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 The number of geometric isomers that can   exist for square planar \left [ Pt(Cl)(py)(NH_{3}) (NH_{2}OH)\right ]^{+}\: is\: (py=pyridine)

  • Option 1)

    2

  • Option 2)

    3

  • Option 3)

    4

  • Option 4)

    6

 

Answers (1)

best_answer

As we learnt in 

Formation of complexs -

'd' block elements formed many types of the complex with different types of legends like H2 O, CN, CO etc called coordination and organometallic compounds.

- wherein

eg\rightarrow [Fe(CN)_{6}]^{3-}
 

[Fe_{2}(CO)_{9}]
 

[Pt(Cl)_{4}]^{--}\:\:etc

 

 \left [ Pt \left ( Cl \right ) \left ( Py \right ) \left ( NH_{3} \right ) \left ( NH_{2}OH \right )\right ]^{+}

Shows 3 Geometric Isomers 

 

 


Option 1)

2

This is option is incorrect. 

Option 2)

3

This is option is correct. 

Option 3)

4

This is option is incorrect. 

Option 4)

6

This is option is incorrect. 

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Plabita

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