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The \deltaG in the process of melting of ice at -15° C is:

  • Option 1)

    \deltaG = -ve

  • Option 2)

    \deltaG = +ve

  • Option 3)

    \deltaG = 0

  • Option 4)

    All of these

 

Answers (1)

As we discussed in

Spontanous process -

\Delta G= \Delta H-\Delta T

 

- wherein

For spontanouse process \Delta G must be negative.

 

Melting of ice is a non spontaneous process.
Therefore \Delta G is positive.


Option 1)

\deltaG = -ve

Incorrect

Option 2)

\deltaG = +ve

Correct

Option 3)

\deltaG = 0

Incorrect

Option 4)

All of these

Incorrect

Posted by

Vakul

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