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Please,please help me - Redox Reaction and Electrochemistry - JEE Main-2

The equivalent conductances of two strong electrolytes at infinite dilution in H_{2}O( where ions move freely through a solution ) at 25°C are given below:

\Lambda ^{\circ}{_{CH_{3}COONa}}= 91.0 S cm^{2}/equiv.

\Lambda ^{\circ}{_{HCl}}=426.2 S cm^{2}/equiv.

What additional information/quantity one needs to calculate \Lambda ^{\circ} of an aqueous solution of acetic acid?

  • Option 1)

    \Lambda ^{\circ}of chloroacetic acid \left ( ClCH_{2}COOH \right )

  • Option 2)

    \Lambda ^{\circ}of\: NaCl

  • Option 3)

    \Lambda ^{\circ} of \: CH_{3}COOK

  • Option 4)

    The limiting equivalent conductance of  H^{+}\left ( \lambda ^{\circ} {_{H^{+}}}\right )

 
Answers (1)
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As we learnt in

Application of Kohlrausch's law -

Calculation of molar conductivities of weak electrolyte at infinite dilution.

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According to Kohlrausch’s law, the molar conductivity at infinite dilution (\Lambda ^{\circ}) for weak electrolyte, CH_{3}COOH\; is

\Lambda ^{\circ}_{CH_{3}COOH}=\Lambda ^{\circ}_{CH_{3}COONa}+\Lambda ^{\circ}_{HCl}-\Lambda ^{\circ}_{NaCl}

So, for calculating the value of  \Lambda ^{\circ}_{CH_{3}COOH} , value  of \Lambda ^{\circ}_{NaCl} should also be known.


Option 1)

\Lambda ^{\circ}of chloroacetic acid \left ( ClCH_{2}COOH \right )

This option is incorrect.

Option 2)

\Lambda ^{\circ}of\: NaCl

This option is correct.

Option 3)

\Lambda ^{\circ} of \: CH_{3}COOK

This option is incorrect.

Option 4)

The limiting equivalent conductance of  H^{+}\left ( \lambda ^{\circ} {_{H^{+}}}\right )

This option is incorrect.

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