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  • Radiation with wavelength 6561  falls on a metal surface to produce photoelectrons. The electrons are made to enter a uniform magnetic f

Radiation with wavelength 6561 \overset{o}{A} falls on a metal surface to produce photoelectrons. The electrons are made to enter a uniform magnetic field of 3\times 10^{-4}T. If the radius of the largest circular path followed by the electrons is 10mm, the work function (in eV)  of the metal is close to:
Option: 1 1.1
Option: 2 0.8
Option: 3 1.8
Option: 4 1.6
 

Answers (1)

best_answer

 

 

From photoelectric equation:- 

\\KE_{max} = E - \phi \\ = \frac{12400}{\lambda (\ln A)} - \phi \quad (in \ eV) \\\therefore r = \frac{\sqrt{2mKE}}{eB}

\\KE_{max} = \frac{r^2e^2B^2}{2m}

                   = \frac{r^2e2B^2}{2m} \quad (in \ eV)

\therefore \phi = \frac{12400}{6556} - \frac{r^2eB^2}{2m}

          =1.1 eV

Hence the option correct option is (1) .  

Posted by

avinash.dongre

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