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  • Reaction rate between two substance Pond Q is expressed as follows rate <img alt="\mathrm{=k[P]^x[Q]^y}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%3Dk%5BP%5D%5Ex%5BQ%5D

Reaction rate between two substance Pond Q is expressed as follows rate \mathrm{=k[P]^x[Q]^y}.If the concentration of P is doubled and concentration of Q is made half of Initial concentration, the ratio of the new rate to the earlier rate will be

Option: 1

\mathrm{2^{x-y}}


Option: 2

x+y


Option: 3

x / y


Option: 4

x-y


Answers (1)

best_answer

\mathrm{\begin{aligned} & \text { Rate }_1=k[P]^x[Q]^y \\ & \text { Rate } 2= k[2 P]^x\left[\frac{1}{2} Q\right]^y \\ & \text { Rate2 }=\frac{k[2 P]^x\left[\frac{1}{2} Q\right]^y}{k[P]^x[Q]^y}=(2)^x\left(\frac{1}{2}\right)^y \\ & \text { Rate1 } \\ &=2^x \cdot(2)^{-y} \\ &=2^{x-y} \end{aligned}}

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