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Suppose you have taken a dilute solution of oleic acid in such a way that its concentration becomes 0.01 cm 3 of oleic acid per cm 3 of the solution. Then you make a thin film of this solution (monomolecular thickness) of area 4 cm2 by considering 100 spherical drops of radius \left ( \frac{3}{40 \pi} \right )^{\frac{1}{3}}\times 10^{-3}cm. Then the thickness of oleic acid layer will be x\times 10^{-14}m. Where x is __________.
Option: 1 25
Option: 2 30
Option: 3 35
Option: 4 40

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\begin{array}{l} 4 t _{ T }=100 \times \frac{4}{3} \pi r ^{3} \\\\ =100 \times \frac{4 \pi}{3} \times \frac{3}{40 \pi} \times 10^{-9}=10^{-8} cm ^{3} \\\\ t _{ T }=25 \times 10^{-10} cm \\\\ =25 \times 10^{-12} m \\\\ t _{0}=0.01 t _{ T }=25 \times 10^{-14} m \\\\ =25 \end{array}

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Deependra Verma

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