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The box 1 contains chips numbered $3,6,9,12$ and 15. The box 2 contains chips numbered 11 , 16,21 and 26 . Two chips, one from each box are drawn at random.

The number written on these chips are multiplied. The probability for the product to be an even number is ________

Option: 1

\frac{6}{25}


Option: 2

\frac{2}{5}


Option: 3

\frac{3}{5}


Option: 4

\frac{19}{25}


Answers (1)

best_answer

Product will be odd only when (Either both even) or (1st even, 2nd odd) or (IInd even, 1st odd)

So Req. Prob. = P(even & even) +P(even & odd) + P(odd & even)

                       =\left(\frac{2}{3} \times \frac{3}{5}\right)+\left(\frac{2}{5} \times \frac{2}{5}\right)+\left(\frac{3}{5} \times \frac{3}{5}\right)=\frac{19}{25}

Posted by

Rakesh

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