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The correct order of intensity of colors of the compounds is :
Option: 1 \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}>\left[\mathrm{NiCl}_{4}\right]^{2-}>\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}
Option: 2 \left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}>\left[\mathrm{NiCl}_{4}\right]^{2-}>\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}
Option: 3 \left[\mathrm{NiCl}_{4}\right]^{2-}>\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}>\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}
Option: 4 \left[\mathrm{NiCl}_{4}\right]^{2-}>\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}>\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}

Answers (1)

best_answer

Intensity of color is due to greater number of photons during d-d transitions. These transitions will be greater in complexes having lesser splitting because of low energy barrier.

The given complexes can be arranged in order  of their splitting on the basis of complex type and also the ligand involved as

\\\left[N{i}\left(CN)_{4}\right]^{2-}>\left[N_{i}\left(H_{2} O\right)_{6}\right]^{2+}>\left[N_{i} Cl_{4}\right]^{2-}\right.\\ \text{Square planar}\: \: \: \: \: \: \: \text{Octahedral}\: \: \: \: \: \: \: \: \: \text{Tetrahedral}\\ \text{Strongest ligand}\: \: \: \: \: \: \text{weaker ligand}\: \: \: \: \: \text{Weakest ligand}

So, the order of intensity is

\left[\mathrm{NiCl}_{4}\right] ^{2-}>\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}>\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}

Hence, the correct answer is option (3)

Posted by

sudhir.kumar

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