Get Answers to all your Questions

header-bg qa

The diameter of a spherical bob is measured using a vernier callipers. 9 divisions of the main scale, in the vernier callipers, are equal to 10 divisions of vernier scale. One main scale division is 1 \mathrm{~mm}. The main scale reading is 10 \mathrm{~mm}$ and $8^{\text {th }} division of vernier scale was found to coincide exactly with one of the main scale division. If the given vemier callipers has positive zero error of 0.04 \mathrm{~cm}, then the radius of the bob is _________\times 10^{-2} \mathrm{~cm}.
 

Answers (1)

best_answer

9MSD=10VSD\\

1MSD=1mm\\

LC=1MSD-1VSD=0.1MSD\\

MSR=10mm\\

VCD\: or\: VSD=8\\

Zero \ \ error=+0.04cm\\

Reading(Diameter)=MSR+VSR+Zero \ \ correction\\

                                         =10mm+LC\times VCD+\left ( -Zero\: error \right )\\

                                         =10mm+\left ( 0.1 \right )\times8+\left ( -0.4mm \right )\\

Diameter=10.4mm

Radius=5.2mm=52\times10^{-2}cm

Posted by

Ritika Jonwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE