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The field lines of the charges are shown in figure The ratio \mathrm{\frac{q_1}{q_2}} will be.

Option: 1

2


Option: 2

4


Option: 3

5


Option: 4

3


Answers (1)

best_answer

It field lines emerge from \mathrm{q_1} and  q2 while terminate towards \mathrm{q_2} are 4
\mathrm{ \frac{q_1}{q_2}=\frac{12}{4}=3 }
The charge \mathrm{q_2} is negative.

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Rishi

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