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  • The frequency of tunning forks A and B are respectively 3% more and 2% less than the frequency of tunning fork C. When A and B are simultsneously excited, 5 beats per second are produced.Then the f

The frequency of tunning forks A and B are respectively 3% more and 2% less than the frequency of tunning fork C. When A and B are simultsneously excited, 5 beats per second are produced.Then the frequency of the tunning fork A (in Hz) is -

Option: 1

98


Option: 2

100


Option: 3

103


Option: 4

105


Answers (1)

best_answer

Let n be the frequency of fork C, then

\mathrm{n_A=n+\frac{3 n}{100}=\frac{103 n}{100}}

and \mathrm{n_B+n-\frac{2 n}{100}=\frac{98 n}{100}}

but \mathrm{\begin{aligned} & n_A-n_B=5 \\ & \frac{5 n}{100}=5 \\ & n=100 \mathrm{~Hz} . \\ & n_A=\frac{103 \times 100}{100}=103 \mathrm{~Hz} . \end{aligned}}

Posted by

rishi.raj

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