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The graph between two temperature scales P and Q is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal divisions of scale P and 100 divisions on scale Q . The relationship for conversion between the two scales is given   by :-
 
 

Option: 1

\frac{t_{p}}{100}= \frac{t_{Q}-180}{150}


Option: 2

\frac{t_Q}{150}=\frac{t_P-180}{100}


Option: 3

\frac{t_p}{180}-\frac{t_Q-40}{100}


Option: 4

\frac{t_Q}{100}=\frac{t_P-30}{150}


Answers (1)

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\begin{aligned} & \frac{\mathrm{t}_{\mathrm{p}}-30}{180-30}=\frac{\mathrm{t}_{\mathrm{Q}}-0}{100-0} \\ & \frac{\mathrm{t}_{\mathrm{p}}-30}{150}=\frac{\mathrm{t}_{\mathrm{Q}}}{100} \\ & \frac{\mathrm{t}_{\mathrm{Q}}}{100}=\frac{\mathrm{t}_{\mathrm{P}}-30}{150} \end{aligned}

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Shailly goel

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