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The increasing order of  \mathrm{pK_{b }} values of the following compounds is :
Option: 1 II<IV<III<I 
Option: 2 II<I<III<IV   
Option: 3I<II<III<IV     
Option: 4 I<II<IV<III
 

Answers (1)

best_answer

 

III contains -M and -I group, hence it is the least basic.

IV contains -I group

I contains +M group and is more basic than II.

Thus order of strength: I > II > IV > III.

Order of \mathrm{pK_{b}} : I < II < IV < III.

Therefore, Option(4) is correct.

Posted by

Kuldeep Maurya

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