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  • The intensity of gamma radiation from a given source is . On passing through of

The intensity of gamma radiation from a given source is I. On passing through 36 \mathrm{~mm} of lead, it is reduced to \frac{\mathrm{I}}{8}. The thickness of lead which will reduce the intensity of \frac{I}{2} will be:

Option: 1

12 mm


Option: 2

18 mm


Option: 3

9 mm


Option: 4

6 mm


Answers (1)

best_answer

\text { As } \mathrm{I}=\mathrm{I}_0 \mathrm{e}^{-\mu \mathrm{x}}

\therefore \quad \frac{1}{8}=\mathrm{e}^{-\mu 36}                             (i)

\text { and } \frac{1}{2}=e^{-\mu x}                              (ii)

From eq. (i), we ge

\left(\frac{1}{2}\right)^3=\mathrm{e}^{-\mu 36}

Using (ii), we get

\text { or } \mathrm{e}^{-3 \mu \mathrm{x}}=\mathrm{e}^{-\mu 36} \quad \text { or } \quad \mathrm{x}=\frac{36}{3}=12 \mathrm{~mm}

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Nehul

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