The IUPAC name of the following comound is:
Option: 1 5-Bromo-3-methylcyclopentanoic acid
Option: 2 4-Bromo-2-methylcyclopentane carboxylic acid
Option: 3 3-Bromo-5-methylcyclopentanoic acid
Option: 4 3-Bromo-5-methylcyclopentane carboxylic acid
-COOH group has more seniority than others.
At 2 branched carbon preferred.
At 4 there is Br
So, counting will be
So, IUPAC Name
4-Bromo-2-methylcyclopentane carboxylic acid
Therefore, the correct option is (2).
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