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The number of neutrons released when \mathrm{{ }_{92} U^{235}} undergoes fission by absorbing \mathrm{{ }_0 n^1} and \mathrm{\left({ }_{56} B a^{144}+{ }_{36} K r^{89}\right)} are formed, is

Option: 1

0


Option: 2

1


Option: 3

2


Option: 4

3


Answers (1)

best_answer

\mathrm{{ }_{92} U^{235}+{ }_0 n^1 \rightarrow{ }_{92} U^{236}} and

\mathrm{{ }_{92} U^{236} \rightarrow_{56} \mathrm{Ba}^{144}+{ }_{36} \mathrm{Kr}^{89}+3_0 n^1+Q}.

Posted by

Shailly goel

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