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  • The pair in which both the species have the same magnetic moment (spin only) is:Option: 1 <img alt="\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} \text { and }\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6

The pair in which both the species have the same magnetic moment (spin only) is:
Option: 1 \left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} \text { and }\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}
Option: 2 \left[\mathrm{Co}(\mathrm{OH})_{4}\right]^{2-} \text { and }\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}
Option: 3 \left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} \text { and }\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)\right]^{2+}
Option: 4 \left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} \text { and }\left[\mathrm{CoCl}_{4}\right]^{2-}

Answers (1)

best_answer

For solving need to know the concept of WFL (weak field ligand) and SFL (strong field ligand).

Electronic configuration and unpaired electrons of given complexes-

 

Thus complex [Cr(H2O)6]2+ and [Fe(H2O)6]2+ have the same no. of unpaired e- and hence same magnetic moment (spin only).

Therefore, the correct option is (1).

Posted by

Kuldeep Maurya

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