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  • The pitch of the screw gauge is 1mm and there are 100 divisions on the circular scale. When nothing is put between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first lin

The pitch of the screw gauge is 1mm and there are 100 divisions on the circular scale. When nothing is put between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale divisions is clearly visible while 72nd divisions on circular scale coincides with the reference line. The radius of wire is:
Option: 1 0.82 mm
Option: 2 1.80 mm
Option: 3 1.64 mm
Option: 4 0.90mm

Answers (1)

best_answer

\text{Least count}=\frac{\text{pitch}}{\text{no. of div}} =\frac{1 \mathrm{~mm}}{100}=0.01 \mathrm{~mm}

\text{zero error} =+8 \times \mathrm{LC}=+0.08 \mathrm{~mm}

\begin{array}{l} \text{True reading (Diameter) }\\=(1 \mathrm{~mm}+72 \times \mathrm{LC})-\text { (Zero error) } \\ =(1 \mathrm{~mm}+72 \times 0.01 \mathrm{~mm})-0.08 \mathrm{~mm} \\ =1.72 \mathrm{~mm}-0.08 \mathrm{~mm} \\ =1.64 \mathrm{~mm} \end{array}
\text { therefore, radius }=\frac{1.64}{2}=0.82 \mathrm{~mm}

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