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  • The ratio of the shortest wavelength of two spectral series of hydrogen spectrum is found to be about <img alt="9" src="https://lh4.googleusercontent.com/-569M6AcrSWPVp-rnMgQFMYv4RVytufjZZepKTYSc8z

The ratio of the shortest wavelength of two spectral series of hydrogen spectrum is found to be about 9. The spectral series are:

Option: 1

Lyman and Paschen


Option: 2

Balmer and Brackett


Option: 3

Brackett and Pfund


Option: 4

Paschen and Pfund


Answers (1)

best_answer

As we have learnt,

The ratio of the shortest wavelength of two spectral series of the hydrogen spectrum is given as below:
\mathrm{\frac{(\Delta E_{Lyman})_{max}}{(\Delta E_{Paschen})_{max}}=\, \frac{13.6\times 2^{2}(\frac{1}{2}-\frac{1}{\infty})}{13.6\times 2^{2}(\frac{1}{9}-\frac{1}{\infty})}}

Thus, we have,
\mathrm{\frac{(\Delta E_{Lyman})_{max}}{(\Delta E_{Paschen})_{max}}=\frac{9}{1}}

Thus the spectral series are: Lyman and Paschen

Therefore, Option(1) is correct

Posted by

Riya

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