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  • The resultant amplitude due to superposition of two harmonic waves expressed by - <img alt="\mathrm{ \begin{aligned} & y=a \sin (\omega t-k x) \\ & y=a \cos (k x-\omega t) \end{al

The resultant amplitude due to superposition of two harmonic waves expressed by -

\mathrm{ \begin{aligned} & y=a \sin (\omega t-k x) \\ & y=a \cos (k x-\omega t) \end{aligned} } will be -

Option: 1

O


Option: 2

a


Option: 3

\sqrt{2} a


Option: 4

2a


Answers (1)

best_answer

The two waves have a phase difference of \frac{\pi}{2}, hence

Resultant amplitude \begin{aligned} a_r & =\sqrt{a^2+a^2} \\ & =\sqrt{2 a} \end{aligned}

Posted by

Pankaj Sanodiya

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