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The volume in ml of 0.02\; M K_{2}\; Cr_{2}\; O_{7} soln. required to react with 0.288gm of ferrous oxalate in acidic medium is (Molar mass of  Fe=56\; g/mol)
Option: 1 50
Option: 2 -
Option: 3 -
Option: 4 -

Answers (1)

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The reaction occurs as follows:

\mathrm{Fe(C_{2}O_{4})\: +\: K_{2}Cr_{2}O_{7}\: \rightarrow \: Fe^{3+}\: +\: CO_{2}\: +\: Cr^{3+}}

From law of equivalence, we know:

meq of Fe(C2O4) = meq of K2Cr2O7

\mathrm{\frac{0.288}{144}\: x\: 3\: =\: \frac{6\: x\: 0.02\: x\: V}{1000}}

Thus, V = 50

Thus, volume in ml required of K2Cr2O7 is 50.

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Kuldeep Maurya

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