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Three isomers A, B and C (mol. formula C8H11N) give the following results : 
R has lower boiling point than S  \mathrm{B} \xrightarrow[]{\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}} alkali-insoluble product A, B and C, respectively are :
Option: 1
Option: 2
Option: 3
Option: 4

Answers (1)

best_answer

The reaction will be - 

R (Intramolecular H-bonding) has a lower boiling point than S (Intermolecular H-bonding) because of different types of H-bonding.

Therefore, Option 2 is correct.

Posted by

Kuldeep Maurya

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