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Three particles having a charge of 10 \mu c are placed at the corners of an equilateral triangle of side 10 \mathrm{~cm}. The electrostatic potential energy of the system is (Given \frac{1}{4 \pi \epsilon _{0}}=9 \times 10^{9} \mathrm{N- \textrm {m } ^ { 2 }} / \mathrm{c})

Option: 1

Zero


Option: 2

\text{Infinete} \left ( \infty \right )


Option: 3

27 \, J


Option: 4

100 \, J


Answers (1)

best_answer


U=3 \times \frac{1}{4 \pi \epsilon _{0}} \frac{10 \times 10^{-6} \times 10^{2} \times 10^{-6}}{10 \times 10^{-2}}

U=\frac{3 \times 10^{-10}}{4 \pi \epsilon_{0} \times 10^{-3}}

U=\frac{3 \times 10^{-1}}{4 \pi \epsilon _{0}}=3 \times 10^{-1} \times 9 \times 10^{9} \times 10^{-9}
                               = 27\, J Ans.
                              
 

Posted by

Shailly goel

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