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  • To generate a power of 3.2 mega watt, the number of fissions of per minute is (Energy released per fission

To generate a power of 3.2 mega watt, the number of fissions of \mathrm{U^{235}} per minute is
(Energy released per fission \mathrm{=200 \, \mathrm{MeV}, 1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J}})

Option: 1

6 \times 10^{18}


Option: 2

6 \times 10^{17}


Option: 3

10^{17}


Option: 4

6 \times 10^{16}


Answers (1)

best_answer

Number of fissions per second

=\frac{\text { Power output }}{\text { Energy released per fission }}
=\frac{3.2 \times 10^6}{200 \times 10^6 \times 1.6 \times 10^{-19}}=1 \times 10^{17}
\Rightarrow \text { Number of fission per minute }=60 \times 10^{17}=6 \times 10^{18}

Posted by

Irshad Anwar

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