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  • To generate power of 3.2 MW, the number of fissions of  per minute

To generate power of 3.2 MW, the number of fissions of { }^{235} \mathrm{U} per minute (Energy \, \, released \, per\, fission=200$ $\left.\mathrm{MeV}, 1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J}\right)

Option: 1

6 \times 10^{18}


Option: 2

6 \times 10^{17}


Option: 3

10^{17}


Option: 4

6 \times 10^{16}


Answers (1)

best_answer

Here, Power =3.2 \mathrm{MW}=3.2 \times 10^6 \mathrm{~W}

Energy released per fission =200\, \mathrm{MeV}

=200 \times 10^6 \mathrm{eV}=200 \times 10^6 \times 1.6 \times 10^{-19} \mathrm{~J}

\text { Number of fissions per minute }=\frac{3.2 \times 10^6 \times 60}{200 \times 10^6 \times 1.6 \times 10^{-19}}=6 \times 10^{18}

Posted by

Rishabh

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