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  • Two identical charged particles each having a mass 10 g and charge <img alt="\mathrm{2.0 \times 10^{-7}C}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B2.0%20%5Ctimes%2010%5E%7B

Two identical charged particles each having a mass 10 g and charge \mathrm{2.0 \times 10^{-7}C} are placed on a horizontal table with a separation of L between them such that they stay in limited equilibrium. If the coefficient of friction between each particle and the table is 0.25, find the value of L. (Use \mathrm{g=10ms^{-2}}]

Option: 1

12 cm


Option: 2

10 cm


Option: 3

8 cm


Option: 4

5 cm


Answers (1)

best_answer

\mathrm{f_{L} \rightarrow} Limiting friction
\mathrm{F \rightarrow} Electrostatic repulcion fora

\mathrm{\begin{aligned} &F=\frac{k q^{2}}{L^{2}}=\mu m g \\ &f_{L}=\mu N=\mu\; mg \end{aligned} }
for limited equlibrikm,

\mathrm{ \begin{aligned} &F =f_{L} \\ & \frac{k q^{2}}{L^{2}} =\mu \mathrm{mg} \\ & \frac{9 \times 10^{9} \times\left(2 \times 10^{-7}\right)^{2}}{L^{2}}=\left (\frac{1}{4} \right ) \times 10^{-2} \times 10 \\ &L^{2} =9 \times 16^{-4} \times 10^{-4} \\ & L =12 \times 10^{-2} \mathrm{~m}=12 \mathrm{~cm} \end{aligned} }
The correct option is (1)

Posted by

Suraj Bhandari

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