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Two loops with sides L and 1(L>>1) are placed concentrically and coplanar as shown in figure. The mutual inductance of the system is proportional to
                                        

Option: 1

1^2 / \mathrm{L}^2


Option: 2

\mathrm{L}^2 / 1^2


Option: 3

1 / \mathrm{L}^2


Option: 4

1^2 / \mathrm{L}


Answers (1)

best_answer

The value of B is given by
\mathrm{B}=\frac{2 \sqrt{2} \mu_0 \mathrm{i}}{\pi \mathrm{L}}
The flux linked with the smaller loop
\mathrm{\begin{aligned} & \phi=\mathrm{MI}=\mathrm{BA}=\mathrm{Bl}^2 \\ & \therefore \mathrm{Mi}=\frac{2 \sqrt{2} \mu_0 \mathrm{il}^2}{\pi \mathrm{L}} \\ & \text { or } \mathrm{M} \propto \mathrm{l}^2 / \mathrm{L} \end{aligned}}

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